SignTool.exe verify /pa returns exit code 1 from the code but works fine while running from command prompt

hi,

i using signtool.exe new process() verify codesigned assembly , returns exit code 1 whereas returns exit code 0 while run same visual studio command prompt. please let me know thoughts...

here code snippet vs2012 ultimate on win7 pc.

p = new process();

            p.startinfo.filename = "c:\\program files (x86)\\microsoft sdks\\windows\\v7.0a\\bin\\signtool.exe";

            string args = @"verify";

            p.startinfo.arguments =  args + " "+ "/pa " + "/v "+ name;

            p.start();

            p.waitforexit();

            pexitcode = p.exitcode;

//name = "c:\\users\\v-maparn\\documents\\visual studio 2012\\projects\\codesignverification\\codesignverification\\bin\\release\\microsoft.it.core.dll"

thanks,

mani

hi mani,

you welcome.

it seems there wrong vb.net code.

please copy microsoft.it.security.ui.systemsecuritymanagement.ssmuiwebhost.dll file c:\\ folder, try run this vb.net code below:

process p = new process(); p.startinfo.filename = "c:\\program files (x86)\\microsoft sdks\\windows\\v7.0a\\bin\\signtool.exe"; string args = @"verify";              string name = "c:\\microsoft.it.security.ui.systemsecuritymanagement.ssmuiwebhost.dll"; p.startinfo.arguments = args + " " + "/pa " + "/v " + name;              p.start();  p.waitforexit();  int pexitcode = p.exitcode; messagebox.show(pexitcode.tostring());

hope helps!

amy

Windows Server  >  Security